%>%
operator)dplyr
is a package for data wrangling, with several key
verbs (functions)filter()
: subset rows based on a conditiongroup_by()
: define groups of rows according to a
conditionsummarize()
: apply computations across groups of
rowsarrange()
: order rows by value of a columnselect()
: pick out given columnsmutate()
: create new columnsmutate_at()
: apply a function to given columnstidyr
is a package for manipulating the structure of
data framespivot_longer()
: make “wide” data longerpivot_wider()
: make “long” data widerString basics
The simplest distinction:
Character: a symbol in a written language, like letters, numerals, punctuation, space, etc.
String: a sequence of characters bound together
class("r")
## [1] "character"
class("Ryan")
## [1] "character"
Why do we care about strings?
Whitespaces count as characters and can be included in strings:
" "
for space"\n"
for newline"\t"
for tabstr = "Dear Mr. Carnegie,\n\nThanks for the great school!\n\nSincerely, Ryan"
str
## [1] "Dear Mr. Carnegie,\n\nThanks for the great school!\n\nSincerely, Ryan"
Use cat()
to print strings to the console, displaying
whitespaces properly
cat(str)
## Dear Mr. Carnegie,
##
## Thanks for the great school!
##
## Sincerely, Ryan
The character is a basic data type in R (like numeric, or logical), so we can make vectors or matrices of out them. Just like we would with numbers
str.vec = c("Statistical", "Computing", "isn't that bad") # Collect 3 strings
str.vec # All elements of the vector
## [1] "Statistical" "Computing" "isn't that bad"
str.vec[3] # The 3rd element
## [1] "isn't that bad"
str.vec[-(1:2)] # All but the 1st and 2nd
## [1] "isn't that bad"
str.mat = matrix("", 2, 3) # Build an empty 2 x 3 matrix
str.mat[1,] = str.vec # Fill the 1st row with str.vec
str.mat[2,1:2] = str.vec[1:2] # Fill the 2nd row, only entries 1 and 2, with
# those of str.vec
str.mat[2,3] = "isn't a fad" # Fill the 2nd row, 3rd entry, with a new string
str.mat # All elements of the matrix
## [,1] [,2] [,3]
## [1,] "Statistical" "Computing" "isn't that bad"
## [2,] "Statistical" "Computing" "isn't a fad"
t(str.mat) # Transpose of the matrix
## [,1] [,2]
## [1,] "Statistical" "Statistical"
## [2,] "Computing" "Computing"
## [3,] "isn't that bad" "isn't a fad"
Easy! Make things into strings with as.character()
as.character(0.8)
## [1] "0.8"
as.character(0.8e+10)
## [1] "8e+09"
as.character(1:5)
## [1] "1" "2" "3" "4" "5"
as.character(TRUE)
## [1] "TRUE"
Not as easy! Depends on the given string, of course
as.numeric("0.5")
## [1] 0.5
as.numeric("0.5 ")
## [1] 0.5
as.numeric("0.5e-10")
## [1] 5e-11
as.numeric("Hi!")
## Warning: NAs introduced by coercion
## [1] NA
as.logical("True")
## [1] TRUE
as.logical("TRU")
## [1] NA
Use nchar()
to count the number of characters in a
string
nchar("coffee")
## [1] 6
nchar("code monkey")
## [1] 11
length("code monkey")
## [1] 1
length(c("coffee", "code monkey"))
## [1] 2
nchar(c("coffee", "code monkey")) # Vectorization!
## [1] 6 11
Substrings, splitting and combining strings
Use substr()
to grab a subsequence of characters from a
string, called a substring
phrase = "Give me a break"
substr(phrase, 1, 4)
## [1] "Give"
substr(phrase, nchar(phrase)-4, nchar(phrase))
## [1] "break"
substr(phrase, nchar(phrase)+1, nchar(phrase)+10)
## [1] ""
substr()
vectorizesJust like nchar()
, and many other string functions
presidents = c("Clinton", "Bush", "Reagan", "Carter", "Ford")
substr(presidents, 1, 2) # Grab the first 2 letters from each
## [1] "Cl" "Bu" "Re" "Ca" "Fo"
substr(presidents, 1:5, 1:5) # Grab the first, 2nd, 3rd, etc.
## [1] "C" "u" "a" "t" ""
substr(presidents, 1, 1:5) # Grab the first, first 2, first 3, etc.
## [1] "C" "Bu" "Rea" "Cart" "Ford"
substr(presidents, nchar(presidents)-1, nchar(presidents)) # Grab the last 2
## [1] "on" "sh" "an" "er" "rd"
# letters from each
Can also use substr()
to replace a character, or a
substring
phrase
## [1] "Give me a break"
substr(phrase, 1, 1) = "L"
phrase # "G" changed to "L"
## [1] "Live me a break"
substr(phrase, 1000, 1001) = "R"
phrase # Nothing happened
## [1] "Live me a break"
substr(phrase, 1, 4) = "Show"
phrase # "Live" changed to "Show"
## [1] "Show me a break"
Use the strsplit()
function to split based on a
keyword
ingredients = "chickpeas, tahini, olive oil, garlic, salt"
split.obj = strsplit(ingredients, split=",")
split.obj
## [[1]]
## [1] "chickpeas" " tahini" " olive oil" " garlic" " salt"
class(split.obj)
## [1] "list"
length(split.obj)
## [1] 1
Note that the output is actually a list! (With just one element, which is a vector of strings)
strsplit()
vectorizesJust like nchar()
, substr()
, and the many
others
great.profs = "Nugent, Genovese, Greenhouse, Seltman, Shalizi, Ventura"
favorite.cats = "tiger, leopard, jaguar, lion"
split.list = strsplit(c(ingredients, great.profs, favorite.cats), split=",")
split.list
## [[1]]
## [1] "chickpeas" " tahini" " olive oil" " garlic" " salt"
##
## [[2]]
## [1] "Nugent" " Genovese" " Greenhouse" " Seltman" " Shalizi" " Ventura"
##
## [[3]]
## [1] "tiger" " leopard" " jaguar" " lion"
strsplit()
needs to return a list
now?Finest splitting you can do is character-by-character: use
strsplit()
with split=""
split.chars = strsplit(ingredients, split="")[[1]]
split.chars
## [1] "c" "h" "i" "c" "k" "p" "e" "a" "s" "," " " "t" "a" "h" "i" "n" "i" "," " " "o"
## [21] "l" "i" "v" "e" " " "o" "i" "l" "," " " "g" "a" "r" "l" "i" "c" "," " " "s" "a"
## [41] "l" "t"
length(split.chars)
## [1] 42
nchar(ingredients) # Matches the previous count
## [1] 42
Use the paste()
function to join two (or more) strings
into one, separated by a keyword
paste("Spider", "Man") # Default is to separate by " "
## [1] "Spider Man"
paste("Spider", "Man", sep="-")
## [1] "Spider-Man"
paste("Spider", "Man", "does whatever", sep=", ")
## [1] "Spider, Man, does whatever"
paste()
vectorizesJust like nchar()
, substr()
,
strsplit()
, etc. Seeing a theme yet?
presidents
## [1] "Clinton" "Bush" "Reagan" "Carter" "Ford"
paste(presidents, c("D", "R", "R", "D", "R"))
## [1] "Clinton D" "Bush R" "Reagan R" "Carter D" "Ford R"
paste(presidents, c("D", "R")) # Notice the recycling (not historically accurate!)
## [1] "Clinton D" "Bush R" "Reagan D" "Carter R" "Ford D"
paste(presidents, " (", 42:38, ")", sep="")
## [1] "Clinton (42)" "Bush (41)" "Reagan (40)" "Carter (39)" "Ford (38)"
Can condense a vector of strings into one big string by using
paste()
with the collapse
argument
presidents
## [1] "Clinton" "Bush" "Reagan" "Carter" "Ford"
paste(presidents, collapse="; ")
## [1] "Clinton; Bush; Reagan; Carter; Ford"
paste(presidents, " (", 42:38, ")", sep="", collapse="; ")
## [1] "Clinton (42); Bush (41); Reagan (40); Carter (39); Ford (38)"
paste(presidents, " (", c("D", "R", "R", "D", "R"), 42:38, ")", sep="", collapse="; ")
## [1] "Clinton (D42); Bush (R41); Reagan (R40); Carter (D39); Ford (R38)"
paste(presidents, collapse=NULL) # No condensing, the default
## [1] "Clinton" "Bush" "Reagan" "Carter" "Ford"
Reading in text, summarizing text
How to get text, from an external source, into R? Use the
readLines()
function
king.lines = readLines("https://www.stat.cmu.edu/~arinaldo/Teaching/36350/F22/data/king.txt")
class(king.lines) # We have a character vector
## [1] "character"
length(king.lines) # Many lines (elements)!
## [1] 59
king.lines[1:3] # First 3 lines
## [1] "Five score years ago, a great American, in whose symbolic shadow we stand today, signed the Emancipation Proclamation. This momentous decree came as a great beacon light of hope to millions of Negro slaves who had been seared in the flames of withering injustice. It came as a joyous daybreak to end the long night of their captivity."
## [2] ""
## [3] "But 100 years later, the Negro still is not free. One hundred years later, the life of the Negro is still sadly crippled by the manacles of segregation and the chains of discrimination. One hundred years later, the Negro lives on a lonely island of poverty in the midst of a vast ocean of material prosperity. One hundred years later..."
(This was Martin Luther King Jr.’s famous “I Have a Dream” speech at the March on Washington for Jobs and Freedom on August 28, 1963)
We don’t need to use the web; readLines()
can be used on
a local file. The following code would read in a text file from
Professor Rinaldo’s computer:
king.lines.2 = readLines("~/Dropbox/Teaching/36-350/36-350_F22/webpage/data/king.txt")
This will cause an error for you, unless your folder is set up exactly like Professor Rinaldo’s laptop! So using web links is more robust
Fancy word, but all it means: make one long string, then split the words
king.text = paste(king.lines, collapse=" ")
king.words = strsplit(king.text, split=" ")[[1]]
# Sanity check
substr(king.text, 1, 150)
## [1] "Five score years ago, a great American, in whose symbolic shadow we stand today, signed the Emancipation Proclamation. This momentous decree came as a"
king.words[1:20]
## [1] "Five" "score" "years" "ago," "a"
## [6] "great" "American," "in" "whose" "symbolic"
## [11] "shadow" "we" "stand" "today," "signed"
## [16] "the" "Emancipation" "Proclamation." "This" "momentous"
Our most basic tool for summarizing text: word
counts, retrieved using table()
king.wordtab = table(king.words)
class(king.wordtab)
## [1] "table"
length(king.wordtab)
## [1] 622
king.wordtab[1:10]
## king.words
## - ...the ...to 'tis 100 1963 a able Again
## 29 2 1 1 1 1 1 37 8 1
What did we get? Alphabetically sorted unique words, and their counts = number of appearances
Note: this is actually a vector of numbers, and the words are the names of the vector
king.wordtab[1:5]
## king.words
## - ...the ...to 'tis
## 29 2 1 1 1
king.wordtab[2] == 2
## -
## TRUE
names(king.wordtab)[2] == "-"
## [1] TRUE
So with named indexing, we can now use this to look up whatever words we want
king.wordtab["dream"]
## dream
## 9
king.wordtab["Negro"]
## Negro
## 13
king.wordtab["freedom"]
## freedom
## 18
king.wordtab["equality"] # NA means King never mentioned equality
## <NA>
## NA
Let’s sort in decreasing order, to get the most frequent words
king.wordtab.sorted = sort(king.wordtab, decreasing=TRUE)
length(king.wordtab.sorted)
## [1] 622
head(king.wordtab.sorted, 20) # First 20
## king.words
## of the to and a be will is that
## 98 97 57 40 37 32 29 25 23 23
## as freedom in we from have our I Negro not
## 19 18 18 18 17 17 16 14 13 13
tail(king.wordtab.sorted, 20) # Last 20
## king.words
## walk, wallow warm waters, well were When
## 1 1 1 1 1 1 1
## whirlwinds whites whose winds with. withering wrongful
## 1 1 1 1 1 1 1
## wrote yes, York York. You your
## 1 1 1 1 1 1
Notice that punctuation matters, e.g., “York” and “York.” are treated as separate words, not ideal—we’ll learn just a little bit about how to fix this on lab, using regular expressions
Let’s use a plot to visualize frequencies
nw = length(king.wordtab.sorted)
plot(1:nw, as.numeric(king.wordtab.sorted), type="l",
xlab="Rank", ylab="Frequency")
A pretty drastic looking trend! It looks as if \(\mathrm{Frequency} \propto (1/\mathrm{Rank})^a\) for some \(a>0\)
This phenomenon, that frequency tends to be inversely proportional to a power of rank, is called Zipf’s law
For our data, Zipf’s law approximately holds, with \(\mathrm{Frequency} \approx C(1/\mathrm{Rank})^a\) for \(C=100\) and \(a=0.65\)
C = 100; a = 0.65
king.wordtab.zipf = C*(1/1:nw)^a
cbind(king.wordtab.sorted[1:8], king.wordtab.zipf[1:8])
## [,1] [,2]
## of 98 100.00000
## the 97 63.72803
## to 57 48.96336
## and 40 40.61262
## a 37 35.12930
## be 32 31.20338
## 29 28.22840
## will 25 25.88162
Not perfect, but not bad. We can also plot the original sorted word counts, and those estimated by our formula law on top
plot(1:nw, as.numeric(king.wordtab.sorted), type="l",
xlab="Rank", ylab="Frequency")
curve(C*(1/x)^a, from=1, to=nw, col="red", add=TRUE)
We’ll learn about plotting tools in detail a bit later
nchar()
, substr()
: functions for substring
extractions and replacementsstrsplit()
, paste()
: functions for
splitting and combining stringstable()
: function to get word counts, useful way of
summarizing text data